Polynomial Remainder Theorem

Theorem: Remainder of division of a polynomial $f(x)$ by a linear factor $(x-a)$ is $f(a)$

Prerequisites:
Euclidean Polynomials Division (proof)

Proof:
Any polynomial can be written according to the Euclidean polynomial division as:

$\qquad\quad f(x) = q(x)g(x) + r(x)\qquad\text{where }\;\; deg\big(r(x)\big) < deg\big(g(x)\big)\qquad\qquad\ldots (1)$

Here $q(x)$, $g(x)$ and $r(x)$ are the quotient, divisor and remainder respectively and $deg(.)$ represents the degree of the respective polynomial.

Since $g(x) = (x-a)$, therefore  $deg\big(g(x)\big) = 1$

Hence, $deg\big(r(x)\big) = 0$
$\Rightarrow \quad\;\; r(x) = r =$ constant
$\therefore \qquad\! r(x)$ is independent of $x$.

Putting $x=a$ and $g(x) = (x-a)$ in equation $(1)$,
$\qquad\quad f(a) = q(a)(a-a) + r\\ \Rightarrow\;\quad\; f(a) = r$

Hence the result


Recommended:
Factor Theorem
Factor representation of polynomials