Theorem: Vertically opposite angles formed by a pair of intersecting lines are equal
Prerequisites:
Angle on a straight line (proof)
Proof:
In the given figure, $\angle AOD$ and $\angle BOC$ are vertically opposite. Similarly, $\angle AOC$ and $\angle BOD$ are vertically opposite.
Since angle at a point on a straight line is $180^o$, hence due to line CD,
$\quad\qquad\angle AOD + \angle AOC = 180^o\\
\therefore\quad\;\; \angle AOD = 180^o - \angle AOC\qquad\qquad\qquad\qquad\text{$...(1)$}$
Also, due to line AB,
$\quad\qquad \angle AOC + \angle BOC = 180^o\\
\therefore\quad\;\; \angle BOC = 180^o - \angle AOC\qquad\qquad\qquad\qquad\text{$...(2)$}$
Hence, from $(1)$ and $(2)$,
$\qquad\quad\angle AOD = \angle BOC$
Similarly,
$\qquad\quad\angle AOC = \angle BOD$
Hence the result.
Recommended:
Corresponding angles theorem
Alternate angles theorem
Interior angles theorem
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