Theorem: If two pairs of angles of two triangles are equal in measurement, and the included sides are equal in length, then the triangles are congruent.
Prerequisites:
Unique ASA triangle (proof)
Proof:
Let there be two triangles $\triangle ABC$ and $\triangle DEF$, such that the angles $\angle ABC = \angle DEF$, $\angle ACB = \angle DFE$ and the included sides BC $=$ EF.
Since for the given two angles and an included side, a unique triangle can be formed (see prerequisite), hence both the triangles are congruent.
Q.E.D.
Recommended:
Unique ASA triangle
SSS congruence
SAS congruence
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